TEST GUIDELINES
Answers should be indicated by placing a tick mark ( ) in the relevant box.
To change any answer already marked, cancel the previous mark by placing an= symbol. Thereafter, place a fresh tick mark ( ).
All questions have only one right answer. If more than one answer is indicated, the question will not be evaluated.
Use of Calculators; log tables etc. is not permitted.
The duration of this test is strictly 60 minutes. In case you continue to answer beyond 60 minutes, your sheet will not be evaluated.
Any attempt to impersonate will be viewed seriously.
SECTION A
Directions : For each question in this section, select the best of the choices given
#define AND &&
#define OR ||
#define LE =
main( )
{
char ch = D;
if((ch GE 65 AND ch LE 90) OR (ch GE 97 AND ch LE 122))
printf(Alphabet);
else
printf(Not an alphabet);
}
a) No Alphabet b) Alphabet c) error d)None
main( )
{
int n[25];
n[0] = 100;
n[24] = 200;
printf(%d %d, *n, *(n + 24) + *(n + 0));
}
a) 200 100 b) 100 300 c) 100 200 d) None
main( )
{
int arr[ ] = { 0, 1, 2, 3, 4};
int i, *ptr;
for(ptr = arr + 4; ptr = arr; ptr--)
printf(%d, *ptr);
}
a) 0 1 2 3 4 b) 4 3 2 1 0 c) 1 2 3 4 0 d)None
main( )
{
struct employee
{
char name[25];
int age;
float bs;
};
struct employee e;
e.name = Hacker;
e.age = 25;
printf(%s%d, e.name, e.age);
}
a) Hacker, 25 b) Error message c) 25 Hacker d) None
#define NULL 0
main( )
{
struct node
{
struct node *previous;
int data;
struct node *next;
} ;
struct node *p, *q;
p = malloc(sizeof(struct node));
q = malloc(sizeof (struct node));
p->data = 75;
q->data = 90;
p->previous = NULL;
p->next = q;
q->previous = p;
q->next = NULL;
while(p!=NULL)
{
printf(%d\n, p->data);
p =p->next;
}
}
a) 90 b) 75 c) 90 d) None 75 90 90
main( )
{
int i=3;
i=i++;
printf(%d,i));
}
a. 3 b. 4 c. undefined d. Error
What error would the following function give on compilation.
f (int a,int b)
{
int a;
a=20;
return a;
}
#define sqr(x) (x*x)
main( )
{
int a,b=3;
a=sqr(b+2);
printf(%d,a);
}
a. 25 b. 11 c. Error d. Garbage value
#define str(x) #x
#define Xstr(x) str(x)
#define oper multiply
main( )
{
char *opername=Xstr(oper);
printf(%s,opername);
}
a. oper b. multiply c. Error d. None
main( )
{
printf(%c,abcdefgh[4]);
}
a. a b. e c. Error d. None
main( )
{
printf(%d %d %d,sizeof(3),sizeof(3),sizeof(3));
}
a. 1 1 1 b. 2 2 2 c. 1 2 2 d. 1 1 1
Note: Assume size of int is 2 bytes.
main( )
{
struct emp{
char n[20];
int age;}
struct emp e1={david,23};
struct emp e2=e1;
if(e1= = e2) printf(structures are equal);
}
main( )
{
char a[ ];
a[0] = A;
printf(%c, a[0]);
}
a) Compilaltion Error
b) No output
c) A
d) None
main( )
{
int x = 5;
printf(%d %d, x++, ++x);
return 0;
}
a) Error b) 6, 6 c) 5, 7 d) 7, 6
main( )
{
int z = 4;
printf( %d, printf( %d %d , z, z));
}
a) 4 4 3 b) 4 4 5 c) 4 4 4 d) Error
int i = 0;
main( )
{
printf(i = %d, i);
i++;
val( );
printf(After i=%d, i);
val( );
}
val( )
{
i =100;
printf(vals i=%d\n, i);
i++;
}
a) i =0 b) i=0 c) Error d) None of the above
vals i=100 vals i =100
i =1 i=101
vals i =100 vals i =100
main( )
{
int a[ ] = { 10, 20, 30, 40, 50};
int j;
for (j = 0; j < 5; j++)
{
printf( \n %d, * a);
a ++;
}
}
a) 0..5 b) 0..4 c) Error d) None of the above
main( )
{
int a[5] = {2, 4, 6, 8, 10);
int i, b =5;
for(i=0; i0);
i = i +n;
}
The end value of i is
(a)210 (b) 20 ( c) -1 (d) 200
main( )
{
int i = 0; char ch = A
do {
printf(%c, ch);
} while (i++
