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Technical - C & C++ by Persistent

Details of Technical - C & C++ by Persistent conducted by Persistent for job interview.
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MODE: CAMPUS
RECRUITMENT FOR: Development/Testing

The test consisted of a 1hr technical objective
questions and 1hr ,Programming test. Tech. Qs
There were six sections and each consist of 5qs.

Computer Algorithms
1. Time Complexity
2. Which of the following cannot be implemented
List
1. Quicksort
3. Polynomials
4. Insertion Sort
5. Binary Search
3. In binary search tree , n=nodes, h=height of tree.
What,s complexity?
1. o(h)
2. o(n*h)
3. o(nLogn)
4. o(n*n)
5. None
4.
5.

C Programs
1. Printf("%d%d",i++,i++);
1. Compiler Dependent
2. 4 4
3. 4 3
4. 3 4
5. None of Above
2. void main()
{
printf("persistent");
main();
}
1. Till stack overflows
2. Infinite
3. 65535
4. 34423
5. None
3. Swapping
4. what does it do?
void f(int n)
{
if(n>0)
{
if(A[i]>A[j])
swap();
}
else
f(n-1);
}
1. Swap
2. Sort in Ascending order
3. Sort in Descending order
4. Computes permutation
5.
5. Given a Fibonacci function
f1=1;f2=1
fn=f(n-1)+f(n-2) which of the following is true?
1. Every Second element is even
2. Every third element is odd
3. The series increases monotonally
4. For n>2, fn=ceiling(1.6 * f(n-1))
5. None

Operating System
1. Where the root dir should be located
1. Anywhere on System disk
2. Anywhere on Disk,
3. In Main memory
4. At a fixed location on Disk
5. At fixed location on System Disk
2. Problem on Concurrency
3. Problem on Round Robin Algorithm
4.
5.

General
1. If x is odd, in which of the following y must be
even
1. X+Y=5
2. 2(X+Y)=7
3. 2X + Y =6
4. X+2Y=7
5.
2. 1000! How many digits? What is the most significant
and Least significant

digit
3.
4.
5.

Theory
1. If a production is given
S -> 1S1
0S0
00
11
Then which of the following is invalid
1. 00101010100
2.
3.
4.
5.
2. Context free grammar cannot recognize
1. if-then-else
2. var
3. loops
4. syntax
5. None
3.
4.
5.

DBMS
1. If table A has m rows and table B has n rows then
how many rows will the
following query return
SELECT A.A1,B.B1
FROM A,B
WHERE A.A3=B.B3
1.