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Aptitude - Puzzle - 26 July 2003 by Honeywell

Details of Aptitude - Puzzle - 26 July 2003 by Honeywell conducted by Honeywell for job interview.
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Honeywell Campus Test at NCE,Kovilpatti on July 26 2003. 

  Aptitude:

Questions from  Simple train pbms,age,ratio, proportion,Profit ,loss,Time & work,Time & Distance,Pipe &

Cisterns,Shaded aream,Volume ( cylinder ,cone ..),Reasoning,2 sections a part 

with 4 questions b part with 6 questions

There must 4 domocrats & 3 republicans out of the 12 professors.No of X professors are A,B,C,D. No of Y professors are E,F,G,H,I.If A comes f & G r absent ..

so on.

There must 4 domocrats & 3 republicans out of the 12 professors.No of X professors are A,B,C,D. No of Y professors are E,F,G,H,I.If A comes f & G r absent ..

so on.

2. Technical(Computer Science)

OS,cache access time -100ns,Primary memory access time -1000ns,...then some data & 

condition, find the actual access time.,microprocessor ( lot of questions )  8085 no of16 bit registers.,8086 Instruction queue byte length?,8088 Instruction queue

byte length?,6800 what is it?8085 pgms...,port no calculationsData StructuresWhich

Data Structures to use for infix to prefix conversion,Worst case complexity for quick sort,preorder traversal Binary tree ...

int *data[10];whatdoes the variable data denotes?

{
  int a[]={10,20,30,40,50};

  fun(a+1);

    }

  fun(int *p)

 { for(int i=1;i<=3;i++)

  printf("%d",*(p+i));}

enum day { saturday,sunday=3,monday,tuesday};

value of saturday,tuesday.4. enum day {saturday,sunday=-1,monday,tuesday};

 int x=monday;value of x?5. #define ADD(X,Y) 

 X+Ymain(){-#undef ADD(X,Y) fun();

 }

 fun()
  {
  int y=ADD(3,2);
  printf("%d",y);
  }
  o/p?  

#define ADD(X,Y) X+Y
    main()
    {
      #undef ADD;
     fun();
    }
   fun()
     {
      #if not defined(ADD)
     define ADD(X+Y) X*Y
     int y=ADD(3,2);
     printf("%d",y);
   }
   o/p?

int x;                                                                                                 
int *p;
int **p1;
int ***p2;

 How to assign each one?